Upload Local Image to Web API in C#

The /UploadJpeg endpoint is part of a Web API designed for License Plate Recognition (LPR) and Vehicle Make & Model (VMM) processing. This endpoint allows users to upload a JPEG image, which will then be analyzed by the system to extract license plate information and detect vehicle characteristics.

This API accepts a POST request with the image file included as multipart/form-data. Once the image is successfully uploaded, it becomes available for further processing by the LPR/VMM engine.

Below is an example in C# demonstrating how to upload a .jpg image using HttpClient:

using System;
using System.IO;
using System.Net.Http;
using System.Threading.Tasks;

class Program
{
    static async Task Main()
    {
        var filePath = @"C:\Path\To\Your\File.jpg"; // Replace with your JPEG file path
        var url = "http://84.200.6.42:5000/UploadJpeg";

        using var client = new HttpClient();
        using var multipartContent = new MultipartFormDataContent();
        using var fileStream = File.OpenRead(filePath);
        using var fileContent = new StreamContent(fileStream);

        fileContent.Headers.ContentType = new System.Net.Http.Headers.MediaTypeHeaderValue("image/jpeg");
        multipartContent.Add(fileContent, "file", Path.GetFileName(filePath));

        var response = await client.PostAsync(url, multipartContent);

        if (response.IsSuccessStatusCode)
        {
            Console.WriteLine("Upload successful.");
            var responseContent = await response.Content.ReadAsStringAsync();
            Console.WriteLine("Response: " + responseContent);
        }
        else
        {
            Console.WriteLine($"Upload failed. Status code: {response.StatusCode}");
            var errorContent = await response.Content.ReadAsStringAsync();
            Console.WriteLine("Error: " + errorContent);
        }
    }
}

Notes: #

• Make sure the file path exists and points to a valid .jpg or .jpeg file.
• This assumes the server expects a multipart/form-data with a file field.
• Adjust "file" in multipartContent.Add(...) if the API expects a different key name (though Swagger shows none, this is usually “file”).